Identify which quadrant contains the terminal side of an angle in standard position with each given degree measure with 75 degrees, 120 degrees, -30 degrees, and -200 degrees

75° quadrant I

120°  quadrant II

–30° quadrant IV

–200° quadrant II    

Step-by-step explanation:

just did it and these were the answers

75= |

120= ||

-30= |V

120 = ||

Step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet