Find an equation for the line perpendicular to 2x+ 6y = 30 and goes through the point (6,2)
Write your answer in the form y= mx + b.

y = 3x - 16

Step-by-step explanation:

We are asked to find the equation of the line perpendicular to 2x + 6y = 30

We can use two formulas for this question, either

y = mx + c. Or

y - y_1 = m(x - x_1)

Step 1: calculate the slope

From the equation given

2x + 6y = 30

Make y the subject of the formula

6y = 30 - 2x

Or

6y = -2x + 30

Divide both sides by 6, to get y

6y/6 = ( -2x + 30)/6

y = (-2x + 30)/6

Separate them in order to get the slope

y = -2x/6 + 30/6

y = -1x/3 + 5

y = -x/3 + 5

Slope = -1/3

Step 2:

Note: if two lines are perpendicular to the other, both are negative reciprocal of each other

Perpendicular slope = 3/1

Substitute the slope into the equation

y = mx + c

y = 3x + c

Step 3: substitute the point into the equation

( 6,2)

x = 6

y = 2

2 = 3(6) + c

2 = 18 + c

Make the c the subject

2 - 18 =c

c = 2 - 18

c = -16

Step 4: sub the value of c into the equation

y = 3x + c

y = 3x - 16

The equation of the line is

y = 3x - 16

If you try out the other formula, u will get the same answer

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step-by-step explanation: