What is the remainder when x^{6}-4x^4+4x^2-10 is divided by x+3?

431

Step-by-step explanation:

Let

We want to find the remainder when this polynomial is divided by x+3.

We use the remainder theorem.

Which says that, when p(x) is divided by x-a, the remainder is p(a)=R.

Therefore the remainder when p(x) is divided by x+3 is p(-3).

We evaluate:

We multiply to get;

We simplify to get:

Therefore the remainder is 431

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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