For a particular cable, the radius of the base of the inner layer is 2 millimeters (mm) and the radius of the base of the outer layer is 6 mm. What is the percent of the area of the base pf the outer layer is the area of the inner layer?

Step-by-step explanation:

The formula for determining the area of a circle is expressed as

Area = πr²

Where

π is a constant whose value is 3.14

r represents the radius of the circle.

Considering the inner layer

radius = 2 millimeters

Area of base = 3.14 × 2² = 12.56 mm²

Considering the outer layer,

Radius = 6 mm

Area of base = 3.14 × 6² = 113.04 mm²

Percent of the area of the base of the outer layer that is the area of the base of the inner layer is

12.56/113.04 × 100 = 11.1%

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

idk

step-by-step explanation:

i don't know