If someone could work out the first half of the problem and explain that would be great!

x = -5

y = -5

Step-by-step explanation:

If you multiply the top equation by negative 2, you can add it to the bottom equation and cancel out the x:

-2(-x + 5y = -20) --> 2x - 10y = 40

Add this to the bottom equation top to bottom:

2x - 10y = 40

-2x + 4y = -10

You get:

-6y = 30

Then solve for y:

y = -5

Plug this back in for either equation and solve for x:

-x + 5(-5) = -20

-x -25 = -20

-x = 5

x = -5

Your answers are:

x = -5

y = -5

x =-5

y = -5

Step-by-step explanation:

-x + 5y = -20 1

-2x + 4y = -10 2

Multiply eqn 1 by 2 and eqn 2 by 1

This is done to make coefficients of x in both equations the same so that x can be eliminated

-2x + 10y = -40

-2x + 4y = -10

Subtracting

6y = -30

y = -5

Substitute y = -5 in eqn 1

-x+5×-5=-20

-x - 25= -20

-x = -20+25 = 5

x = -5

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.