How many grams of a 10% cream must be mixed with 2% cream to prepare 60 grams of a 5% cream?

22.5 grams of 10% cream is mixed with 37.5 grams of 2 % cream to prepare 60 grams of 5% cream.

Step-by-step explanation:

Let x grams of 10% cream is mixed with y grams of 2 % cream to prepare 60 grams of 5% cream.

So, x + y = 60 ............ (1) and

⇒ 10x + 2y = 300

⇒ 5x + y = 150 ............ (2)

Now, solving equations (1) and (2) we get,

4x = 150 - 60 = 90

⇒ x = 22.5 grams

So, y = 60 - x = 37.5 grams. (Answer)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

to have more of what you want like money

step-by-step explanation:

save it by not spending on unnecessary stuff and have more