For which interval is the average rate of change of f(x) negative?

On a coordinate plane, a function starts from above quadrant two and goes through (negative 4, 0) to (negative 3, negative 3). The function then curves upward toward (0, 1) and then curves down toward (3, negative 3). The function then curves up and approaches x = 5.

from x = –4 to x = –1
from x = –3 to x = 3
from x = 0 to x = 2.5
from x = 3 to x = 4.5

The correct option is C

Step-by-step explanation:

I got a 100% on edge2020

from x= 0 to x = 2.5

Step-by-step explanation:

There fore the answer is C

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

whats the question?

step-by-step explanation: