Linda invest a total of $10,000 into savings account one account to pay 6% interest in the other piece 7% find them a place in each account is the account receive a total of $660 in interest after one year use interest equals principal times rate times time

she invested $4000 at 6% and $6000 at 7%

Step-by-step explanation:

Let x represent the amount which she invested in the account paying 6% interest.

Let y represent the amount which she invested in the account paying 7% interest.

Linda invest a total of $10,000 into 2 savings account, one account to pay 6% interest and the other pays 7%. This means that

x + y = 10000

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account paying 6% interest,

P = $x

T = 1 year

R = 6℅

I = (x × 6 × 1)/100 = 0.06x

Considering the account paying 7% interest,

P = $y

T = 1 year

R = 7℅

I = (y × 7 × 1)/100 = 0.07y

If she receives a total of $660 in interest after one year, it means that

0.06x + 0.07y = 660 - - - - - - - - - -1

Substituting x = 10000 - y into equation 1, it becomes

0.06(10000 - y) + 0.07y = 660

600 - 0.06y + 0.07y = 660

- 0.06y + 0.07y = 660 - 600

0.01y = 60

y = 60/0.01

y = 6000

x = 10000 - y = 10000 - 6000

x = 4000

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