‘a’ is an element which belongs to period 3, having 6 electrons in its valence shell. below is a list of successive ionization energies (in kj/mol) for period 3. ie2 = 2250 ie3 = 3360 ie4 = 4560 ie5 = 7010 ie6 = 8500 ie7 = 27,100 identify the element ‘a’

The element A is S (sulfur)

Explanation:

The elements for the 3erd period in the periodic table are Na, Mg, Al, Si, P, S, Cl and Ar.

The one that has 6 e⁻ in its valence shell is the S, because it is missing 2 e⁻ to reach the octet rule. 2 e⁻ to has the most stable noble gas conformation.

The IE of S = 3360 kJ/mol

It is a little lower than Cl because the electron is so far from the nucleus, that's why we have to apply a very low ionization energy to rip the electron off.

here's the link to your question!

explanation: