Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the class declares that a score of 70 or higher is required for a grade of at least "C." Using the 68-95-99.7 rule, what percent of students score below 62? Remember that it helps to sketch the curve.

The percent of students who scored below 62 is 2.3%.

Step-by-step explanation:

In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is used to represent that 68.27%, 95.45% and 99.73% of the values of a Normally distributed data lie within one, two and three standard deviations of the mean, respectively.

Then,

Given:

μ = 78

σ = 8

X = 62

Compute the distance between the value of X and μ as follows:

Use the relation P (-2 < Z < 2) ≈ 0.9545 to compute the value of P (Z < -2) as follows:

The percentage is, 0.02275 × 100 = 2.275% ≈ 2.3%

Thus, the percent of students who scored below 62 is 2.3%.

blue marble is 15 times out of 50 = 15/50 reduces to 3/10

landing on tails is 24 out of 50 = 24/50 reduces to 12/25

to find the probability of both multiply together:

3/10 x 12/25 = 3 x 12 / 10 x 25 = 36/250

if you multiplied the numerator and denominator by 10 you get 360/2500.

the answer is 360/2500

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step-by-step explanation:

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