Mathematics, 05.03.2020 22:08 fatherbamboo
A person standing at the edge of a cliff throws a rock upward from a height of 180ft above ground level with an initial velocity of 64ft/s. Calculate the velocity of the rock when it is exactly 48ft above the person's hand. Separate multiple answers with a comma. (Hint: Use h(t)=−16t2+64t+180 as the position function, where h is in feet, t in seconds. Ignore air resistance.)
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