Can you pls help me out? i would sincerely appreciate it!!

Step-by-step explanation:

Step 1: Given

BD bisects ∠ADC

Step 2: Given

BD ⊥ AC

Step 3: Corresponding Parts of Congruence Triangles are Congruent

∠1 ≅ ∠2

Step 4: By definition of perpendicular

∠ABD = ∠CBD = 90° (BD ⊥ AC )

∠3 and ∠4 are right angles.

Step 5: By CPCTC,

∠3 ≅ ∠4

Step 6: Reflexive postulate

Any side or angle is reflexive to itself.

DB ≅ DB

Step 7: ASA postulate

∠1 ≅ ∠2 (A),   DB ≅ DB (S)   and   ∠3 ≅ ∠4 (A),

∴ ΔABD ≅ ΔCBD (by ASA)

Step 8: By Corresponding Parts of Congruence Triangles are Congruent

DA ≅ DC

Step 9: Opposite sides of a triangle are equal.

ΔACD is isosceles.

Hence proved.

8

step-by-step explanation: