Lines a and b are cut by transversal f. At the intersection of lines f and a, the top left angle is 96 degrees. At the intersection of lines b and f, the bottom right angle is (6 x minus 36) degrees. What must be the value of x so that lines a and b are parallel lines cut by transversal f? 10 20 22 32

answer: it is 1: 47 pm

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2