A fruit stand owner has 90 apples and 72 oranges. He wants to make the greatest number possible of identical bags with a
combination of apples and oranges without any fruit leftover. How many apples are in each bag?
A)
4
E)
18

18 bags

with 90/18 = 5 apples

and 72/18 = 4 oranges

in each bag

Step-by-step explanation:

Step-by-step explanation:

The greatest common Divisor of 90 and 72 is 18

Then

the number of apples in each bag = 90÷18 = 5

the number of oranges in each bag = 72÷18=4

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x