Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how much was it worth, to the nearest hundred dollars?

Property amount after 11 year is $95,250

Property amount = $75,000

Rate of growth = 2.2% annually

Number of year = 11 year

Property amount after 11 year

A = P[1+r]ⁿ

Property amount after 11 year = 75,000[1+0.022]¹¹

Property amount after 11 year = 75,000[1.022]¹¹

Property amount after 11 year = 75,000[1.27]

Property amount after 11 year = $95,250

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When Aria sold her house after eleven years it worth was $95,300.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

The amount of house after eleven years to the nearest hundred dollars is $95,300.

Therefore, when Aria sold her house after eleven years it worth was $95,300.

b

step-by-step explanation:

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles