One side of a triangle is half the longest side. The third side is 8 meters less than the longest side. The perimeter is 52 meters. Find all three sides

Step-by-step explanation:

Side A is the longest side

Side B is half of A = A/2

Side C is 8m less than A = A-8

Perimeter of traingle = A+B+C

52 = A + A/2 + A-8

Collect like terms

52+8= A+A/2+A

60 = 5/2 A

Divide 60 by the coefficient of A

60÷5/2 = A

60×2/5= A

A=24m

Substitute the value of A into the expressions for sides B and C

Side B =A/2=24/2=12m

Side C =A-8=24-8=16m

The sides of the triangle are 24m, 12m and 16m