A normal distribution has a mean of 137 and a standard deviation of 7. Find the z-score for a data value of 121. Incorrect Round to two decimal places g

The z-score for a data value of 121 is -2.29.

Step-by-step explanation:

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Find the z-score for a data value of 121.

This is Z when X = 121. So

The z-score for a data value of 121 is -2.29.

.

Step-by-step explanation:

We have been given that a normal distribution has a mean of 137 and a standard deviation of 7. We are asked to find the z-score corresponding to data value 121.

We will use z-score formula to solve our given problem.

, where,

z = Z-score,

x = Sample score,

= Mean,

= Standard deviation.

Upon substituting our given values in above formula, we will get:

Upon rounding to two decimal places, we will get:

Therefore, z-score corresponding to data value 121 would be .

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: