Simplify the expression given below. I + 2
13 + 212 - 91 - 18
3r + 1
12 9
A.
31+1
1
31 + 1
B.
(1 + 3) (1 3)
OC. 31 + 1
3.1 + 1
(1 + 3)(1 - 3)
OD

A) 1/(3x+1)

Step-by-step explanation:

(x+2)/(x³+2x²-9x-18)÷(3x+1)/(x²-9)

(x+2)/(x+2)(x+3)(x-3)÷(3x+1)/(x+3)(x-3)

since it’s dividing by a fraction, invert and multiply

(x+2)/(x+2)(x+3)(x-3) times (x+3)(x-3)/(3x+1)

The (x+2)’s cancel out.

The (x+3)’s cancel out.

The (x-3)’s cancel out.

You are left with 1/(3x+1)

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

just took the test and my answers down below!

step-by-step explanation:

check the pic :