If $10,000 is invested at 2 percent semi-annually for 5 years, what is the amount at the end of the
term?

Solution:

The formula for compound interest, including principal sum, is:

Where,

A = the future value of the investment including interest

P = the principal investment amount

r = the annual interest rate in decimal

n = the number of times that interest is compounded per unit t

t = the time the money is invested

From given,

p = 10000

t = 2 years

n = 2 ( since interest is compounded semiannually)

Substituting the values in formula,

Thus the amount at the end of the term is $ 11046

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752