Astudent pushes a 12.0 kg box with a horizontal force of 20 n. the friction force on the box is 9.0 n. which of the following is the best approximation of the box’s acceleration?

The acceleration of the box its 0,91 m/s²

Explanation:

According to Newton first law, the force applyed to some object its equal to the mass of the object plus the acceleration of the same object.

   F=m.a ; clearing the acceleration of the equation ⇒ a=F/m

  Now in the problem its apeared the friction force and according to de phsysics definition its a force thats its against of movement.

  So the force its going to be equal to F= 20N - 9N.

 Replacing in the equation a=(20N - 9N)/12kg.

 Solving ⇒ a ≅0, 91 m/s²

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

i would say