Find the equation of a straight line that has a perpendicular bisector of AB.
A = (2,6) B = (5, -2)

Step-by-step explanation:

slope of line through A ,B is

m=(-2-6)/(5-2)=-8/3

slope of line perpendicular to AB Is  3/8

mid-point of AB =((2+5)/2,(6-2)/2)=(7/2,2)

eq. of reqd line is

y-2=3/8(x-7/2)

8y-16=3x-21/2

16y-32=6x-21

16y-6x=-21+32

16y-6x=11

range is infinite on both x and y axis positive and negative

step-by-step explanation:

answer: it's d

step-by-step explanation: