A disk server receives requests from many client machines and requires 8 milliseconds to respond to each request. Let N = the number of additional requests that arrive before the service interval is complete. The probability of exactly k additional requests in the 8-millisecond service interval is P(N = k) = e−0.9(0.9)k/k!, for k = 0,1,2,...,[infinity]. If 2 or more new calls arrive while the service interval is only partially complete, what is the probability that exactly 3 new calls will arrive before the server is ready to respond?
Hint: Use rules for conditional probability.

the probability that exactly 3 new calls will arrive before the server is ready to respond = 0.2165

Step-by-step explanation:

The concept of conditional probability is applied considering the probability of an event which is about to happen when another event had already occured. The steps and appropriate substitution in the equation given is as shown in the attachment.

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you