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simplify each expression.

1) 3(2p - 4) - (p + 8)=

2) -3(n + 3) - (n - 6)=

3) -4(7 + 5b) - 5(7b + 6)=

4) 8(2 - 5p) - (p - 6)

5) 8(n + 2) + 8(2n - 7)

6) -(6x + 4) - 2(-x + 1)

1) 5p - 4     2) -4n - 3   3) -55b -58   4) -41p + 22   5) 24n - 40   6) -4x - 6

Step-by-step explanation:

1) 3(2p - 4) - (p + 8)= 6p - 12 - p + 8  = 5p - 4

2) -3(n + 3) - (n - 6)= -3n - 9 - n + 6 = -4n - 3

3) -4(7 + 5b) - 5(7b + 6)= -28 - 20b - 35b - 30 = -55b -58

4) 8(2 - 5p) - (p - 6)= 16 - 40p - p + 6 = -41p + 22

5) 8(n + 2) + 8(2n - 7)= 8n + 16 + 16n - 56 = 24n - 40

6) -(6x + 4) - 2(-x + 1)= -6x - 4 + 2x - 2 = -4x - 6

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.