In a right triangle δabc, the length of leg ac = 5 ft and the hypotenuse ab = 13 ft. find the length of the angle bisector of angle ∠a.

the length of the angle bisector of angle ∠A is 6 ft

Step-by-step explanation:

The diagram of the right angle triangle ABC is shown in the attached photo

Looking at triangle ABC,

cos θ = adjacent side/hypotenuse side

cos θ = 5/13 = 0.3846

θ = 67.38 degrees

The bisector of an angle divides it into two equal halves. The bisector is represented by line AD.

θ/2 = 67.38/2 = 33.69 degrees

Therefore,

Cos 33.69 = 5/AD

AD × Cos 33.69 = 5

AD = 5/Cos 33.69 = 5/0.832

AD = 6 ft

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47