Abox consists of 14 components, 5 of which are defective.
(a) components are selected and tested one at a time, without replacement, until a non-defective component is
found. let x be the number of tests required. find p(x= 5).
(b) components are selected and tested, one at a time without replacement, until two consecutive non defective
components are obtained. let x be the number of tests required. find p(x= 5).

what is process of getting solution

the answer is 62

17 1/3

step-by-step explanation:

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!