paul has $35000 to invest. his intent is to earn 11% interest on his investment. he can invest part of his money at 8%
interest and part at 14% interest. how much does paul need to invest in each option to make get a total 11% return on
his $35000?
investing for 8% return: $
9
investing for 14% return: $
b

Step-by-step explanation:

The fraction that needs to be invested at the higher rate is ...

  (11% - 8%)/(14% -8%) = 3%/6% = 1/2

Half the money should be invested at each of the rates:

  $17,500 for 8% return

  $17,500 for 14% return.

If you let x represent the amount at the higher rate, then the total return is ...

  14%x + 8%(35000 -x) = 11%(35000)

  (14% -8%)x = (11% -8%)(35000) . . . . subtract 8%·35000

  x = (11% -8%)/(14% -8%)×35000 . . . . divide by the coefficient of x

Note that this formula is exactly the one we started with, above.

your welcome haha, this is the best place to find answers

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !