Arectangular painting has dimensions x + 8. the painting has a frame that is 3 inches wide. the total area of the picture and the frame is 384 inches ^2. find the dimensions of the painting in inches.
1) none of the choices are correct.
2) x² + 20x + 84 = 384
3) x² + 13x + 33 = 384
4) x² + 13x - 351 = 0

The dimensions of the painting are 10 in by 18 in

Step-by-step explanation:

The complete question is

A rectangular painting has dimensions x and x + 8. The painting has a frame that is 3 inches wide. The total area of the picture and the frame is 384 inches ^2. Find the dimensions of the painting in inches

we know that

The area of the painting is

The total area of the picture and the frame is 384 inches ^2

so

----> correct choice

solve the quadratic equation by graphing

using a graphing tool

The solution is x=10 in

see the attached figure

therefore

The dimensions of the painting are 10 in by 18 in

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.