If an object is thrown straight up from the ground what velocity does it need to be thrown in order to reach a height of 50 ft?

Object is thrown with a velocity of 56.74 m/sec

Step-by-step explanation:

We have given height h = 50 feet

When the object reach at its maximum height its final velocity will be o

So final velocity v = 0 m/sec

Acceleration due to gravity ( Negative sign is due to upward direction )

From third equation of motion

So object is thrown with a velocity of 56.74 m/sec

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24