In a lab experiment, 40 bacteria are placed in a petri dish. the conditions are such that the number of bacteria is able to double every 17 hours. how many bacteria would there be after 4 hours, to the nearest whole number?

59 bacteria would there be after 4 hours.

Step-by-step explanation:

Given:

Bacteria in the petri dish = 40

Time taken for the bacteria to be doubled  =17 hours

To Find:

To Find the number bacteria left after 4 hours = ?

Solution:

By using the proportionality,

After 17 hours the number of bacteria will be 80.

Let the number of bacteria after 4 hours be x

then

Now by cross multiplication

x= 18. 82

So the number of bacteria after 4 hours will be

= 40 + 18.82

= 58.82

=59

if this is really you s much. i only have 3 points left and i have 2 questions to ask

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb