Solving a right triangle ‼️ can someone me find b, b, and c❓round to the nearest tenth.

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 given angles from 180 for B

B = 180° - (90 + 39)° = 180° - 129° = 51°

Using the tangent and sine ratios in the right triangle for b and c

tan39° = =

Multiply both sides by b

b × tan39° = 27 ( divide both sides by tan39° )

b = ≈ 7.5 ( to the nearest tenth )

sin39° = =

Multiply both sides by c

c × sin39° = 27 ( divide both sides by sin39° )

c = ≈ 28.0 ( to the nearest tenth )

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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-1/2 +2

step-by-step explanation: