Aferris wheel 50ft in diameter makes one revolution every
2minutes. if the center of the wheel is 30ft above the ground,
howlonger reaching the low point is a rider 50ft above the
ground?

The required function is .

The rider is 50ft above the ground at x=45.56.

Step-by-step explanation:

The general cosine function is

            .... (1)

where, |A| altitude, is period, C/B is phase shift and D is midline.

The center of the wheel is 30ft above the ground. So, D=30.

A Ferris wheel 50ft in diameter makes one revolution every 2 minutes.

Minimum value = 30-25 = 5

It means the equation passes through the point (0,5) and phase shift is 0.

Substitute A=-25, B=π, C=0 and D=30 in equation (1).

Therefore, the required function is .

Substitute y=50 to find the value of x.

Divide both sides by -25.

Divide both sides by π.

Therefore, the rider is 50ft above the ground at x=45.56.

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: