Chemistry, 14.03.2020 06:55 rosemarybooker
The following reaction is spontaneous as written when the components are in their standard states:
3 Zn(s) +2 Cr3+(aq) →3 Zn2+(aq) +2 Cr(s)
If the [Zn2+] is 4 molL−1, determine the value of [Cr3+] below which the reaction will be spontaneous in the opposite direction.
Answers: 3
![\begin{array}{rcl}Q & = & \dfrac{\text{[Zn$^{2+}$]$^{3}$}}{\text{[Cr}^{3+}]^{2}}\\\\64.0 & = & \dfrac{4^{3}}{\text{[Cr}^{3+}]^{2}}\\\\\text{[Cr}^{3+}]^{2}& = & \dfrac{64}{64.0}\\\\& = & 1\\\text{[Cr}^{3+}] & = & \textbf{1 mol/L}\\\end{array}\\\text{[Cr$^{3+}$] must be less than $\large \boxed{\textbf{1 mol/L}}$ for the reaction to be spontaneous in the reverse}\\\text{direction.}](/tpl/images/0547/6685/5fcfe.png)
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The following reaction is spontaneous as written when the components are in their standard states:
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