From a bag with 5 blue and 3 white balls, in how many ways can you pick 2 blue balls and 1 white ball at once?

60ways

Step-by-step explanation:

This has to do with selecting whereas combination deals with selection. If we are selecting r objects from the total number of n objects, we will have nCr = n!/(n-r)!r!

If we are picking 2 blue balls from 5red balls, we have 5C2 = 5!/3!2!

5C2 = 5×4×3!/3!2!

5C2 = 10ways

Similarly, picking 1 white ball from a total of 3balls, we have 3C1

3C1 = 3×2×1

3C1 = 6ways

Picking 2 blue balls and 1 white ball at once results in 5C2 × 3C1 = 10×6 = 60ways

< 6 cm to > 26 cm i believe

step-by-step explanation:

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0