![x\in\Big(-\infty,-\frac{4}{3}\Big] \\x\in(-\infty,-2]](/tpl/images/0437/5120/40ebb.png)
we can rewrite as union of intervals and simplify the union to get solution.![\Big(-\infty,-\frac{4}{3}\Big]\cup(-\infty,-2]\Longrightarrow\boxed{(-\infty,-2]}](/tpl/images/0437/5120/4a619.png)
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