Avi's pet hamster chubby loves to run in his hamster wheel. during one "race", avi counts 100100100 rotations of the wheel. she wants to know how far chubby ran, so she measures the diameter of the wheel and finds that it is 20 \text{ cm}20 cm20, start text, space, c, m, end text.

Distance ran by Avi's pet hamster chubby is 6280 cm.

Step-by-step explanation:

Given:

The diameter of hamster wheel = 20 cm

Now the circumference of hamster wheel is given by :-

where d ⇒ the diameter of the hamster wheel.

During one race, the number of rotations of the wheel = 100

Therefore, the distance run by chubby is given by :-

Distance ran by chubby is equal to the number of rotations of the wheel times Circumference of the wheel.

framing in equation form we get;

D⇒ Distance ran by Chubby.

Hence Distance ran by Avi's pet hamster chubby is 6280 cm.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.