Silva a counted the total number of fish she had caught at the end of each of the last three weeks. her fish counts as shown below. 225, 525, 825 are fish counts follow a pattern. write an expression that can be used to predict the total number of fish she will have caught at the end of n weeks.

F(n) = 225 +(n)300

Step-by-step explanation:

It is given that the fish counts of last 3 weeks are as follows,

225, 525 and 825.

The difference between consecutive terms is 300.

If we carefully look, these are numbers in arithmetic progression, with first term as 225 and common difference as 300.

Thus, at the end of nth week, with initial amount of fish at n=0 as 225, the fish count is given by,

F(n) = 225 +(n)300, where F(n) in function of total number of fishes and n is the number of weeks.

We can verify as, at n=1, F(1) = 225 + 300 = 525 and F(2) = 225 + 600 = 825, which are already correctly given.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

step-by-step explanation: