Find the equation of the line, in slope intercept form that passes through the point (-6,5) and has slope 1/3

y = x/3 + 7

Step-by-step explanation:

Use the equation: y - y1 = m(x - x1)

Plug in the given values into the equation:

y - 5 = (1/3)(x + 6)

Simplify the right side:

y - 5 = (x/3) + 2

Finally, add 5 to both sides:

y = x/3 + 7

b.an increase in a causes b to decrease

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this