The length of a rectangle is four times its width. if the perimeter is at most 106 centimeters, what is the greatest possible value for the width?

which inequality models this problem?

a.) 2w+ 2 • (46) < 106

b.) 2w+ 2 • (46) > 106

c.) 2w+ 2. (46) < 106

d.) 2w+ 2 · (46) > 106

Part a) The inequality that models this problem is

Part b) The greatest possible value for the width is 10.6 centimeters

Step-by-step explanation:

Part a) Which inequality models this problem?

Let

l ----> the length of the rectangle in cm

w ---> the width of the rectangle in cm

we know that

The perimeter  of the rectangle is equal to

Remember that

The term "at most" means "less than or equal to"

so

----> inequality A

---> equation B

substitute equation B in the inequality A

 ---> inequality that model the problem

Part b) what is the greatest possible value for the width?

solve for w

Divide by 10 both sides

therefore

The greatest possible value for the width is 10.6 centimeters

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: