A chi-square test for independence is being used to evaluate the relationship between two variables, one of which is classified into 3 categories and the second of which is classified into 4 categories. The chi-square statistic for this test would have df equal to .

This question is based on Chi-square test. Therefore, the chi-square statistic for this test would have df equal to .

Given:

Chi-square test for independence is being used to evaluate the relationship between two variables . Given "A" is classified into 3 categories . Second 'B' is classified into 4 categories

According to the question,

In this chi-square test, we would be test if two attributes A and B under consideration are independent or not.

Let assumed that,  null Hypothesis : H₀: The two variables are independent

Now, degrees of freedom in chi-square test for independence is,

 ⇒ ν = ( r-1) (s-1)

It is given that, 'r' = 3  and  's' = 4.

Thus, degrees of freedom for independence is,

ν = ( r-1) (s-1) = ( 3-1) ( 4-1) = 2×3 =6

Therefore, test statistic be,

Therefore, the chi-square statistic for this test would have df equal to .

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Degrees of freedom for independence  in chi-square statistic

ν = ( r-1) (s-1) =6

Step-by-step explanation:

Explanation:-

Given data  chi-square test for independence is being used to evaluate the relationship between two variables

Given "A" is classified into 3 categories

Second 'B' is classified into 4 categories

In this chi-square test, we test if two attributes A and B under consideration are independent or not

We will assume that

Null Hypothesis : H₀: The two variables are independent

Degrees of freedom in chi-square test for independence

ν = ( r-1) (s-1)

Given data 'r' = 3  and  's' = 4

Degrees of freedom for independence

ν = ( r-1) (s-1) = ( 3-1) ( 4-1) = 2×3 =6

Test statistic

                       χ ²  =  ∑  

false

step-by-step explanation: