The speed of a river current is 7 mph. if a boat travels 20 miles downstream in the same time that it takes to travel 10 miles upstream find the speed of the boat in still water

  21 mph

Step-by-step explanation:

The relationship between time, speed, and distance is ...

  time = distance/speed

The speed downstream is b+7 if the boat's speed is b. The speed upstream is b-7, and the times in each direction are equal. This means ...

  20/(b+7) = 10/(b-7) . . . . . . time in each direction are the same

  20(b-7) = 10(b+7) . . . . . . . cross multiply

  (20-10)b = 7(10+20) . . . . . add 7(20)-10b

  b = 7(20 +10)/(20 -10) = 21 . . . . mph

The speed of the boat in still water is 21 mph.

idk

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph