An eagle carry a trout flies above a lake along a horizontal path. the eagle drops the trout from a height of 6.1m. the fish travels7.9 m horizontally before hitting the water. what is the velocity of the eagle?

Velocity of the eagle = 7.08 m/s

Explanation:

  We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

  Vertical motion of fish:

      Initial velocity = 0 m/s , acceleration = acceleration due to gravity = , displacement = 6.1 m we need to find time.

 Horizontal motion of fish:

      Acceleration = acceleration due to gravity = , displacement = 7.9 m , time = 1.116 seconds we need to find Initial velocity (u).

    So, velocity of the eagle = 7.08 m/s

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.