Aline is parameterized by x=8+6t x = 8 + 6 t and y=3+2t (a) which of the following points are on the section of the line obtained by restricting t to nonnegative numbers (for each, enter y if the point is on the section, and n if not)? (−4,−1): (26 , 9) : (32,11): then, give one more point that is on the section of the line obtained by this restriction: (b) what are the endpoints of the line segment obtained by restricting t to − 5 ≤ t ≤ − 2 ? left endpoint: right endpoint:

We have the line parametrized by

Solving for t in each equation we have that

The point (a,b) lies in the line if when we replace a in the first equation and b in the second equation, the values of t coincide.

a)

1. (-4,-1)

Then, (-4,-1) lies in the line but no lies in the section of the line obtained by restricting t to nonnegative numbers.

2. (26,9)

Since t is positive then (26,9) lies in the line and lies in the section of the line obtained by restricting t to nonnegative numbers.

3. (32,11)

Since t is positive then (32,11) lies in the line and lies in the section of the line obtained by restricting t to nonnegative numbers.

4. If we take t=2 we obtain the point

(20,7) that lies in the section of the line obtained by restricting t to nonnegative numbers.

b)

When t=-5,

correspond to the point (-22,-7).

when t=-2

correspond to the point (-4,-1).

-22<-4 and -7<-1

then the left endpoint (-22,-7) and right endpoint (-4,-1)

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: