Mathematics, 23.04.2021 21:30 northpolea
Find the average value of ()=6β2 f(x)=6β2x over the interval [0,3].[0,3].
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Evaluate this using ! 0.25^2 x 2.4 + 0.25 x 2.4^2 β 0.25 x 2.4 x 0.65
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Proving the parallelogram diagonal theoremgiven abcd is a parralelogam, diagnals ac and bd intersect at eprove ae is conruent to ce and be is congruent to de
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F(x) = 2x + 1? h(x) = x β h(x) = x + h(x) = x β 2 h(x) = x + 2
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Find the average value of ()=6β2 f(x)=6β2x over the interval [0,3].[0,3]....
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