99 points will give no fake answers!
a computer programmer has a 35% chance of finding a bug in any given program. what is the probability that she finds a bug within the first three programs she examines?
a) 0.15
b) 0.27
c) 0.59
d) 0.73

a fair coin is flipped multiples times until it lands on heads. if the probability of landing on heads is 50%, what is the probability of first landing on heads on the fourth attempts?
a) 0.625
b) 0.0625
c) 0.500
d) 0.382

1.

Chance of finding a bug = 0.35

Chance of not finding a bug = 1 - 0.35 = 0.65

Probability of finding a bug in the first 3 programs =

Probability of not finding a bug in 2 out of the 3 and finding a bug in 1.:

0.65^2 * 0.35 = 0.147 = 0.15

Answer is A.

2.

Probability of heads = 0.50

Probability of tails = 0.50

Probability of heads on the fourth attempt = tails x tails x tails x heads = 0.5 x 0.5 x 0.5 x 0.5 = 0.0625

The answer is B.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x