1.2. for vectors x = (1; 2i; 1 + i)t and y = (i; 2 i; 3)t compute
a) (x; y), kxk2, kyk 2, kyk;
b) (3x; 2iy), (2x; ix + 2y);
c) kx + 2yk. remark: after you have done part
a), you can do parts
b) and
c) without actually computing all vectors involved, just by using the properties of inner product.

the answer is su.k.my? ? co.kc

could you provide figure.

answer: i think you should do the math and pay attention in class : )

step-by-step explanation:

that is truly what   think but if i get the answer i will

step-by-step explanation:

hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45