Let y be the solution of the initial value problem y′′+y=−sin(2x),y(0)=0,y′(0)=0. y″+y=−sin⁡(2x),y(0)=0,y′(0)=0. the maximum value of y is , careful, ypyp probably does not satisfy the ivp. find solution yy and then find the max value (e. g. by critical value y′(x)=0y′(x)=0 or maybe using calculator if you do not see how to solve y′=0y′=0)

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

where is the diagram? shown below where? ?

step-by-step explanation:

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right