Two small pitchers and one large pitcher can hold 8 cups of water. one large pitcher minus one small pitcher constitutes 2 cups of water. how many cups of water can each pitcher hold?

Small pitcher holds 2 cups of water

Large pitcher holds 4 cups of water

Step-by-step explanation:

Let the cups holded by the small pitcher be x and the cups holded by the larger pitch be y

Given Two small pitchers and one large pitcher can hold 8 cups of water

ie  2x+y=8

Also given that  One large pitcher minus one small pitcher constitutes 2 cups of water

ie  y-x=2

subtract those two equation's we get

3x=6

x=2.

substitute this value of x is the second equation we get

y-2=2

y=4

Therefor the number of cups of water holded by small pitcher is 2 and the number of cups of water holded by large pitcher is 4.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

$3,200 x 7.25% = $3,200 x .0725 = $232 interest monthly

$232 monthly x 12 annual = $2, 784

step-by-step explanation: