Aballoon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant it is 64 feet above the ground. a. how many seconds after its release will the bag strike the ground? b. at what velocity will it hit the ground?

a. 2.56 sec

b. 65.96 feet.

Step-by-step explanation:

a) The equation of motion of a body under gravity gives the equation  

......... (1) {Where u is the initial velocity of the body and t is the time to descend h height and g is the acceleration due to gravity.

Now, from the equation (1) we have  

{Since g = 32 feet/sec² }

⇒

So, applying Sridhar Acharya formula  

seconds {Neglecting the negative root as t can not be negative.} (Answer)

b) Again we have the formula that  

{Where v is the final velocity before hitting the ground.}

⇒

⇒ v = 65.96 feet / sec. (Answer)

7

step-by-step explanation:

i'm assuming you need to figure out how many campers go into each tent.

i got the answer by:

24+4=28

28/4=7  

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.