The average of three real numbers is greater than or equal to at least one of the numbers.

The given statement is true.        

Step-by-step explanation:

We are given the following information in the question:

The average of three real numbers is greater than or equal to at least one of the numbers.

We can prove this statement.

Let a, b and c be the three real numbers.

Then, the average of these three real numbers is given by

Let a be the smallest of the three natural number.

Then, we can write,

Let a be the largest number.

Thus, looking at both the inequalities, we can say that the average of three real numbers is greater than or less than equal to one of the numbers.

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x