The molecular weight of acetic acid is 60. how much acetic acid would you need to prepare 10 ml of a 0.001 m (1.0 mm) solution?

When the concentration is reported in terms of M, that signifies the molarity which is in moles of solute per liter solution. In this case, we use the volume to multiply to the molarity to determine the moles of acetic acid. Finally, we use the molar mass to convert moles to mass. The solution is as follows:

0.001 mol/L * 0.01 L * 60 g/mol = 0.0006 g acetic acid

There is no reason to think the results are biased or not conducted properly but you should not assume the results are correct just because they were done in a laboratory so the answer would be c. it is likely to be reliable because the results support the conclusion presented.